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Question

If x=n=0an,y=n=0bn,z=n=0cn where a,b,c are in AP and |a|<1,|b|<1,|c|<1, then x,y,z are in

A
HP
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B
ArithmeticoGeometric Progression
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C
AP
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D
GP
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Solution

The correct option is A HP
Given that,
x=n=0an,y=n=0,z=n=0cn

Now,
x=1+a+a2+.............y=1+b+b2+.............z=1+c+c2+.............x=11ay=11bz=11c

Given a,b,c are in A.P
1a,1b,1c are in A.P
11a,11b,11c are in H.P

Option A is correct answer.

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