If x-t2-1-t2-y-t4-1-t4 then dy-dx equals-

The correct option is A 2x Given, x=t^2+1/t^2 amp; #160; y=t^4+1/t^4 y=t^4+1/t^4+2 2 y= ( t^2+1/t^2 )^2 2 y=x^2 2 dy/dx ...

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Definition of Limit

If x=t2+1/t...

Question

If $x = t^{2} + \frac{1}{t^{2}}, y = t^{4} + \frac{1}{t^{4}}$ then $\frac{d y}{d x}$ equals-

2 x

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x

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x^{2}

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None of these

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Solution

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Similar questions

x = \frac{1 - t^{2}}{1 + t^{2}}, y = \frac{2 t}{1 + t^{2}}

\frac{d y}{d x} = - \frac{x}{y}

x^{2} + y^{2} = t + \frac{1}{t}

x^{4} + y^{4} = t^{2} + \frac{1}{t^{2}}

\frac{d y}{d x} = - \frac{y}{x}

x + y = t - \frac{1}{t}, x^{2} + y^{2} = t^{2} + \frac{1}{t^{2}},

\frac{d y}{d x}

x = \frac{1 - t^{2}}{1 + t^{2}}

y = \frac{2 a t}{1 + t^{2}}

\frac{d y}{d x}

x = \frac{1 - t^{2}}{1 + t^{2}}

y = \frac{2 t}{1 + t^{2}}

\frac{d y}{d x}

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