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Question

If y=x3x62x93... to , then the value of x3 is

A
1+ey
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B
1ey
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C
ey
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D
ey1
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Solution

The correct option is B 1ey
y is nothing but the expansion of loge(1x3).
Now
y=loge(1x3)
ey=1x3
x3=1ey
Hence, option 'B' is correct.

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