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Byju's Answer
Standard XII
Mathematics
Applications of Cross Product
If z1 , z2 ...
Question
If
z
1
,
z
2
,
z
3
are three collinear points in arranged plane , then
∣
∣ ∣
∣
z
1
¯
z
1
1
z
2
¯
z
2
1
z
3
¯
z
3
1
∣
∣ ∣
∣
=
A
0
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B
-1
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C
1
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D
2
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Solution
The correct option is
A
0
If
z
1
,
z
2
z
3
are collinear.
⎡
⎢
⎣
x
1
y
1
z
1
x
2
y
2
z
2
1
1
1
⎤
⎥
⎦
=
0
⎧
⎨
⎩
z
1
=
x
1
+
i
y
1
z
2
=
x
2
+
i
y
2
z
3
=
x
3
+
i
y
3
⎡
⎢
⎣
z
1
¯
z
1
1
z
2
¯
z
2
1
z
3
¯
z
3
1
⎤
⎥
⎦
=
⎡
⎢
⎣
x
1
+
i
y
1
x
1
−
i
y
1
1
x
2
+
i
y
2
x
2
−
i
y
2
1
x
3
+
i
y
3
x
3
−
i
y
3
1
⎤
⎥
⎦
=
⎡
⎢
⎣
x
1
x
1
−
i
y
1
1
x
2
x
2
−
i
y
2
1
x
3
x
3
−
i
y
3
1
⎤
⎥
⎦
+
⎡
⎢
⎣
i
y
1
x
1
−
i
y
1
1
i
y
2
x
2
−
i
y
2
1
i
y
3
x
3
−
i
y
3
1
⎤
⎥
⎦
=
⎡
⎢
⎣
x
1
x
1
1
x
2
x
2
1
x
3
x
3
1
⎤
⎥
⎦
+
⎡
⎢
⎣
x
1
−
i
y
1
1
x
2
−
i
y
2
1
x
3
−
i
y
3
1
⎤
⎥
⎦
+
⎡
⎢
⎣
i
y
1
x
1
1
i
y
2
x
2
1
i
y
3
x
3
1
⎤
⎥
⎦
+
⎡
⎢
⎣
i
y
1
−
i
y
1
1
i
y
2
−
i
y
2
1
i
y
3
−
i
y
3
1
⎤
⎥
⎦
=
0
−
⎡
⎢
⎣
x
1
i
y
1
1
x
2
i
y
2
1
x
3
i
y
3
1
⎤
⎥
⎦
+
⎡
⎢
⎣
i
y
1
x
1
1
i
y
2
x
2
1
i
y
3
x
3
1
⎤
⎥
⎦
+
0
=
0
⎛
⎜
⎝
∵
⎡
⎢
⎣
x
1
i
y
1
1
x
2
i
y
2
1
x
3
i
y
3
1
⎤
⎥
⎦
=
0
⎞
⎟
⎠
So A option is correct.
Suggest Corrections
0
Similar questions
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∣
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¯
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=
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4
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