If $| z_{1} | = | z_{2} | = | z_{3} | = | z_{4} |$ then the points representing $z_{1}, z_{2}, z_{3}, z_{4}$ are

concylic

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vertices of a square

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vertices of a rhombus

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none of these

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Solution

The correct option is A concylic
Let
$| z_{1} | = | z_{2} | = | z_{3} | = | z_{4} | = k$
Then there exists a circle which passes through $z_{1}, z_{2}, z_{3}, z_{4}$ , centered at origin with radius equal to k.
Hence
$z_{1}, z_{2}, z_{3}, z_{4}$ are concyclic.

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If |z1|=|z2|=|z3|=|z4| then the points representing z1,z2,z3,z4 are

The correct option is A concylicLet|z1|=|z2|=|z3|=|z4|=kThen there exists a circle which passes through z1,z2,z3,z4, centered at origin with radius equal to k.Hencez1,z2,z3,z4 are concyclic.

If $| z_{1} | = | z_{2} | = | z_{3} | = | z_{4} |$ then the points representing $z_{1}, z_{2}, z_{3}, z_{4}$ are

The correct option is A concylic
Let
$| z_{1} | = | z_{2} | = | z_{3} | = | z_{4} | = k$
Then there exists a circle which passes through $z_{1}, z_{2}, z_{3}, z_{4}$ , centered at origin with radius equal to k.
Hence
$z_{1}, z_{2}, z_{3}, z_{4}$ are concyclic.