If|z−i|≤2 and z0=5+3i then the maximum value of |iz+z0| is
A
2+√31
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B
7
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C
√31−2
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D
None of these
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Solution
The correct option is B7 |z−i|≤2 z lies on and in the inner part of the circle |z−i|≤2 z0=5+3i From the fig: max(|iz+z0|) will be the distance between point A & point B=[radius of circle (r)] + [distance between point A and center of the circle (d(AC))]. max(|iz+z0|)=max(|z−iz0|)=max(|z−(−3+5i)|)=r+d(AC) ⇒max(|iz+z0|)=2+√(0−(−3))2+(1−5)2=7 Ans: B