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Question

If Z={32+i2}5+{32i2}5,then

A
Re(Z)=0
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B
Im(Z)=0
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C
Re(Z)>0,Im(Z)>0
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D
Re(Z)>0,Im(Z)<0
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Solution

The correct option is B Im(Z)=0
Given, Z=(3+i2)5+(3i2)5

=ei5π6+ei5π6

=ei(ππ6)+ei(πiπ6)

=2cos(5π6)

=232

=3
Hence, Im(Z)=0.

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