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Question

If 2sin2((π2)cos2x)=1cos(πsin2x);x(2n+1)π2,nI, then cos2x is equal to

A
15
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B
35
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C
45
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D
1
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Solution

The correct option is B 35
The given equation is equivalent to
2sin2((π/2)cos2x)=2sin2((π/2)sin2x)
cos2x=sin2x
cosx(cosx2sinx)=0
12tanx=0 as cosx0,
x(2n+1)π/2
tanx=1/2
cos2x=1tan2x1+tan2x=35

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