If distance between the points $(k, 2)$ and (3,4) is $8$ then $k$ =

3 \pm \sqrt{60}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{60}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- \sqrt{60}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

57

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $3 \pm \sqrt{60}$
$A (k, 2)$ and $B (3, 4)$ is $8$ units apart.
$=> {(8)}^{2} = (k - 3)^{2} + (2 - 4)^{2} => 64 = k^{2} - 6 k + 9 + 4 => k^{2} - 6 k - 51 = 0 => k = 3 \pm \sqrt{60}$

Suggest Corrections

Similar questions

A car covers a distance of $60^{k}$ meters in an hour. Calculate the speed of the car in m/sec.

sin

sin (60^{o} - A) sin (60^{o} + A) = k sin 3 A

{sin}^{2} (60^{0} + x) - {sin}^{2} (60^{0} - x) \in [- \frac{k}{2}, \frac{k}{2}]

(a cos 60^{\circ}, 0)

(0, a sin 60^{\circ}, 0)

{cos}^{3} x - {cos}^{3} (60^{0} - x) - {cos}^{3} (60^{0} + x) \in

[- \frac{k}{4} \frac{k}{4}]

k =

Join BYJU'S Learning Program