If dividend = $x^{3} + 13 x^{2} + 32 x + 20$ , divisor = $x^{2} + 11 x + 10$ remainder = 0. Find the quotient q(x)

x + 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x – 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x– 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
x + 2

Given $x^{3} + 13 x^{2} + 32 x + 20$ = $(x^{2} + 11 x + 10)$ q(x)+0

$\begin{matrix} x + 2 x^{2} + 11 x + 10 x^{3} + 13 x^{2} + 32 x + 20 x^{3} + 11 x^{2} + 10 x - ---------------- - 2 x^{2} + 22 x + 20 2 x^{2} + 22 x + 20 - -------------- - 0 \end{matrix}$

Suggest Corrections

Similar questions

If dividend = $x^{4} + x^{3} - 2 x^{2} + x + 1$ , divisor = $x - 1$ and remainder = 2. Find the quotient q(x)

= x + 3,

= x^{3} - 3 x^{2} + 11 x - 16

= 0

When $x^{4} + x^{3} - 2 x^{2} + x + 1$ is divided by x-1, the remainder is 2 and the quotient is q(x). Find q(x).

If dividend = $x^{4} + x^{3} - 2 x^{2} + x + 1$ and divisor = $(x - 1)$ , find the quotient, $q (x)$ and remainder $r (x)$ .

$If the dividend = x^{4} + x^{3} - 2 x^{2} + x + 1, divisor = x - 1 and remainder = 2, then find the quotient q(x) .$

Join BYJU'S Learning Program