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Question

If dividend = x4+x3−2x2+x+1 and divisor = (x−1), find the quotient, q(x) and remainder r(x).


A

q(x) = x3+2x2+x+1 and r(x) = -1

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B

q(x) = -x3+x2+x and r(x) = 4

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C

q(x) = x3+2x2+1 and r(x) = 2

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D

q(x) = x3+2x2+1 and r(x) = 0

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Solution

The correct option is C

q(x) = x3+2x2+1 and r(x) = 2


Given, x4+x32x2+x+1 = (x1)q(x)+r(x)

x3+2x2+1x1x4+x32x2+x+1x4x3––––––2x32x2+x+12x32x2–––––––––x+1x1––––2


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