If dividing the 3 digit number "3BA" by 10 gives 34 without leaving any remainder, the values of B and A are:
2
None of These
Given: 3BA10=34
Since there is no remainder, 3BA is completely divisible by 10.
Now we know that all numbers exactly divisible by 10 will have 0 in the one's place.
⇒ A = 0
Now 3B010=34
So, 3B = 34
⇒ B = 4
Therefore, the number is 340.