If DRIVER = 12, PEDESTRIAN = 20, ACCIDENT = 16 then CAR = ?

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Solution

The correct option is B $6$
Given, DRIVER $= 12$ , PEDESTRIAN $= 20$ and ACCIDENT $= 16$ .
Here, the coded number for each word is obtained by multiplying 2 with the total number of letters in the given word.
So, DRIVER $= 2 \times 6 = 12$ ,
PEDESTRIAN $= 2 \times 10 = 20$ and
ACCIDENT $= 2 \times 8 = 16$
Similarly, CAR $= 2 \times 3 = 6$

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If DRIVER = 12, PEDESTRIAN = 20, ACCIDENT = 16 then CAR = ?

The correct option is B 6Given, DRIVER =12, PEDESTRIAN =20 and ACCIDENT =16.Here, the coded number for each word is obtained by multiplying 2 with the total number of letters in the given word.So, DRIVER =2×6=12, PEDESTRIAN =2×10=20 and ACCIDENT =2×8=16 Similarly, CAR =2×3=6