If $E_{0}$ represents the peak value of the voltage in an ac circuit, the r.m.s. value of the voltage will be[

\frac{E_{0}}{π}

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\frac{E_{0}}{2}

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\frac{E_{0}}{\sqrt{π}}

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\frac{E_{0}}{\sqrt{2}}

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Solution

The correct option is D $\frac{E_{0}}{\sqrt{2}}$
If $E_{0}$ represents the peak value of the voltage in an ac circuit then ,
we know,
$E_{r m s} = \frac{E_{0}}{\sqrt{2}}$

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