Question

# If e1 and e2 are the eccentricities of a hyperbola and its conjugate respectively, Then e−21+e−22=1.False True

Solution

## The correct option is B True We have to remember the relation between the eccentricities of both the hyperbolas with their respectives axes lengths. Here, e21=1+b2a=a2+b2a2 And corresponding parameter for its conjugate hyperbola can be obtained by interchanging the position of  a and b. ife2 is the eccentricity of the conjugate hyperbola,Then, e22=1+a2b2=a2+b2a2

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