If Ea be the electric field intensity due to a short dipole at a point on the axis and Er be that on the right bisector at the same distance from the dipole, then
A
Ea=Er
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B
Ea=2Er
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C
Er=2Ea
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D
Ea=√2Er
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Solution
The correct option is AEa=2Er If q be the charge on one point of the dipole and the half length is equal to d, then the total dipole moment is given by, p = 2qd If Ea be the field at any axial point, then it is given by kpr3 Similarly, the field at any point on the right bisector is given Er=kp2r3 Hence, Ea=2Er