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Question

If E and F are events such that P(E)=14,P(F)=12 and P(EF)=18 find P(EF)

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Solution

P(E)=14,P(F)=12,P(EF)=18

P(EF)=P(EF) [By DE Morgan law]

=1P(EF)

P(EF)=P(E)+P(F)P(EF)

=14+1218

=58

P(EF)=158

=858

=38.

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