If E be chemical equivalent of an element and Z is its electrochemical, then E/Z is measured in

farad

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newton

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coulomb

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faraday

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Solution

The correct option is D faraday
We know that $Faraday constant = \frac{chemical equivalent}{electrochemical equivalent}$
i.e, $F = \frac{E}{Z}$ . Hence $\frac{E}{Z}$ is measured as Faraday constant $F$ .

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