Question

If $E_c=24sin{10}^6\pi t$ and $E_m=12sin500\pi t$ are carrier and modulating signal, then the percentage modulation is

• A. $50$
• B. $60$
• C. $40$
• D. $46$

Answer 1

Answer: (A)

$50$

Here, we have $E_m=12$ and $E_c=24$
Thus, we get $m=\frac{E_m}{E_c}=\frac{12}{24}=0.5=50\%$