If $E_{c e l l} = {E^{0}}_{c e l l}$ for electrochemical cell, than which of the following option is correct?

When

K = 1

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When cell reaction is in equilibrium

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When concentration of solutions of both the half cell is same

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None of the above

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Solution

The correct option is B When $K = 1$
When $E_{c e l l} = {E^{0}}_{c e l l}$
$K = 1$
$E_{c e l l} = E^{0} - \frac{0.059}{n} l o g K_{e q}$
when $l o g K_{e q} = 0$
$E_{c e l l} = E^{0}$
$∴ K_{e q} = 1$

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If Ecell=E0cell for electrochemical cell, than which of the following option is correct?

The correct option is B When K=1When Ecell=E0cellK=1Ecell=E0−0.059nlogKeqwhen logKeq=0Ecell=E0∴Keq=1

If $E_{c e l l} = {E^{0}}_{c e l l}$ for electrochemical cell, than which of the following option is correct?

The correct option is B When $K = 1$
When $E_{c e l l} = {E^{0}}_{c e l l}$
$K = 1$
$E_{c e l l} = E^{0} - \frac{0.059}{n} l o g K_{e q}$
when $l o g K_{e q} = 0$
$E_{c e l l} = E^{0}$
$∴ K_{e q} = 1$