If $\bar{E}$ denote the complement or negation of an even E, what is the value of P(E) + P( $\bar{E}$ ) ?

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Solution

Given: denotes the complement or negation of an event E.

TO FIND:

CALCULATION: We know that sum of probability of occurrence of an event and probability of non occurrence of an event is 1.

Hence

Hence the result is

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