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Question

If Ee,Eα and Ep represents the kinetic energies of an electron, alpha particle and a proton respectively, each moving with same de Broglie wavelength, then:

A
Ee=Eα=Ep
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B
Ee>Ep>Eα
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C
Eα>Ep>Ee
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D
Ee=Ep=Eα
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Solution

The correct option is B Ee>Ep>Eα
P=2m×K.E. and λ=hP, where P is the momentum, K.E. is the kinetic energy and λ is the wavelength.
Same de Broglie wavelength implies the same momentum.
The decreasing order of the mass of the particles is as follows:
α>proton>electron
K.E.=P22m
Hence, Ee>Ep>Eα.

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