If Ee,Eα,Ep represents the kinetic energies of an electron, alpha particle and a proton respectively, each moving with same de-Broglie wavelength then:
A
Ee=Eα=Ep
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B
Ee>Eα>Ep
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C
Eα>Ep>Ee
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D
Ee>Ep>Eα
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Solution
The correct option is DEe>Ep>Eα λ=h√2mE
For constant wavelength, kinetic energy is also inversely proportional to the mass. mα>mp>me
Hence, order of kinetic energy is Ee>Ep>Eα