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Redox Reactions and Couple

If E+Fe2+/F...

Question

If $E_{F e^{2 +} / F e}^{+}$ is $x_{1}$ , $E_{F e^{3 +} / F e}^{+}$ is $x_{2}$ then what will be $E_{F e^{+} / F e^{2 +}}^{+}$ ?

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Solution

By comparing Gibb's free energy,
$∴$ $3 \times x_{2} = E + 2 x_{1}$
$E = 2 x_{1} + 3 x_{2}$

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Similar questions

E_{F e^{3 +} | F e}^{⊖}

E_{F e^{2 +} | F e}^{⊖}

- 0.36 V

- 0.439 V

E_{F e^{3 +} | F e^{2 +}}^{⊖}

Given standard $E^{⊖}$ :

$F e^{3 +} + 3 e^{-} \to F e$ ; $E^{⊖} = - 0.036 V$

$F e^{2 +} + 2 e^{-} \to F e$ ; $E^{⊖} = - 0.440 V$

The $E^{⊖}$ of $F e^{3 +} + e^{-} \to F e^{2 +}$ is:

E_{F e^{2 +} | F e}^{⊖}

E_{F e^{3 +} | F e^{2 +}}^{⊖}

F e^{2 +}, F e^{3 +}

F e

(E^{o})

F e^{3 +} \to F e

F e^{2 +} + 2 e 6 - \to F e; E_{F}^{o} e_{F e^{2 +} / F e} = - 0.47 V

F e^{3 +} + e^{-} \to F e^{2 +}; E_{F e^{3 +} / F e^{2 +}}^{o} = + 0.77 V

(E^{o})

F e^{3 +} \to F e

F e^{2 +} + 2 e^{-} \to F e; E_{F e^{2 +} / F e}^{o} = - 0.47 V

F e^{3 +} + e^{-} \to F e^{2 +}; E_{F e^{3} / F e^{2 +}}^{o} = + 0.77 V

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