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Question

If eiθ=cos θ+i sin θ, then in ABC value of eiA.eiB.eiC

A
-i
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B
1
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C
-1
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D
None of these
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Solution

The correct option is C -1
eiA.eiB.eiC=eiA+iB+iC=ei(A+B+C)=eiπ
[ A+B+C=π]
=cos π+i sin π=(1)+i(0)=1.

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