If E is the energy of the combining atomic orbitals, $E_{1}$ and $E_{2}$ are the energies of molecular orbitals formed, then:

E - E_{1} > E_{2} - E

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E - E_{1} < E_{2} - E

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E - E_{1} = E_{2} - E

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Any one of the above

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Solution

The correct option is B $E - E_{1} < E_{2} - E$
Anti-bonding molecular orbital ( $E_{2}$ ) is raised more in energy than the energy by which bonding molecular orbital ( $E_{1}$ ) is lowered.

Therefore, $E_{2} - E > E - E_{1}$

Hence, the answer is $B$ .

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If E is the energy of the combining atomic orbitals, E1 and E2 are the energies of molecular orbitals formed, then:

The correct option is B E−E1<E2−EAnti-bonding molecular orbital (E2) is raised more in energy than the energy by which bonding molecular orbital (E1) is lowered. Therefore, E2−E>E−E1Hence, the answer is B.

If E is the energy of the combining atomic orbitals, $E_{1}$ and $E_{2}$ are the energies of molecular orbitals formed, then:

The correct option is B $E - E_{1} < E_{2} - E$
Anti-bonding molecular orbital ( $E_{2}$ ) is raised more in energy than the energy by which bonding molecular orbital ( $E_{1}$ ) is lowered.

Therefore, $E_{2} - E > E - E_{1}$

Hence, the answer is $B$ .