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Byju's Answer
Standard VI
Mathematics
Equal Sets
If E = fact...
Question
If E =
{
f
a
c
t
o
r
s
o
f
16
}
and F =
{
f
a
c
t
o
r
s
o
f
20
}
, then E = F
A
True
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B
False
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Solution
The correct option is
B
False
E
=
{
f
a
c
t
o
r
s
o
f
16
}
1
×
16
=
16
,
2
×
8
=
16
,
4
×
4
=
16
E
=
{
1
,
2
,
4
,
8
,
16
}
F
=
{
f
a
c
t
o
r
s
o
f
20
}
1
×
20
=
20
,
2
×
10
=
20
,
4
×
5
=
20
F
=
{
1
,
2
,
4
,
5
,
10
,
20
}
The elements of set E and set F are not same (identical)
Therefore, the given statement is false.
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Similar questions
Q.
In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to
(a) ΔEFC
(b) ΔECF
(c) ΔCEF
(d) ΔFEC