If $E_{n}$ and $E_{m}$ are energy levels of an atom and $E_{m} > E_{n}$ , then the frequencies in the line spectrum of an atom can be calculated by:

\frac{c}{h} [E_{n} - E_{m}]

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R_{H} [E_{n} - E_{m}]

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\frac{c}{h} [E_{m} - E_{n}]

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\frac{1}{h} [E_{m} - E_{n}]

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Solution

The correct option is C $\frac{1}{h} [E_{m} - E_{n}]$
As we know,
$Δ E = h v = E_{m} - E_{n}$
$∴ v = \frac{E_{m} - E_{n}}{h}$

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Similar questions

x^{a} y^{b} = e^{m}, x^{c} y^{d} = e^{n}, △_{1} = ∣ ∣ ∣ \begin{matrix} m & b n & d \end{matrix} ∣ ∣ ∣, △_{2} = ∣ ∣ ∣ \begin{matrix} a & m c & n \end{matrix} ∣ ∣ ∣

△_{3} = ∣ ∣ ∣ \begin{matrix} a & b c & d \end{matrix} ∣ ∣ ∣

x

y

H

E_{n} = - \frac{R h}{9}

R h

1 R h = 2.18 \times 10^{- 18} J

I .

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