If $E_{F e^{3 +} | F e}^{⊖}$ and $E_{F e^{2 +} | F e}^{⊖}$ are $- 0.36 V$ and $- 0.439 V$ , respectively, then the value of $E_{F e^{3 +} | F e^{2 +}}^{⊖}$ is:

(- 36 0.439) V

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[3 (- 0.36) + 2 (- 0.439)] V

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(- 0.36 0.0439) V

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[3 (- 0.36) 2 (- 0.439)] V

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Solution

The correct option is B $[3 (- 0.36) + 2 (- 0.439)] V$
$F e^{3 +} + 3 e^{-} \to F e : Δ G_{1} = - 3 F E_{F e^{3 +} + F e}^{⊖}$
$F e^{2 +} + 2 e^{-} \to F e : Δ G_{2} = - 2 F E_{F e^{2 +} | F e}^{⊖}$
$F e^{3 +} e^{-} \to F e^{2 +} : \to Δ G_{3} = - F E_{F e^{2 +} | F e}^{⊖}$
$E_{F e^{3 +} | F e^{2 +}}^{⊖} = 3 E_{F e^{3 +} | F e}^{⊖} - 2 E_{F e^{2 +} | F e}^{⊖}$
$[3 (- 0.36) + 2 (- 0.439)] V$

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Similar questions

E_{F e^{3 +} / F e^{2 +}}^{0} = - 0.36 V

E_{F e^{2 +} / F e}^{0} = - 0.439 V

E_{F e^{3 +} . F e^{2 +}}^{0}

E_{F e^{3 +} / F e}^{0} = 0.036 V, E_{F e^{2 +} / F e}^{0} = - 0.439 V

F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q)

E_{F e^{2 +} | F e}^{⊖}

E_{F e^{3 +} | F e^{2 +}}^{⊖}

F e^{2 +}, F e^{3 +}

F e

Given standard $E^{⊖}$ :

$F e^{3 +} + 3 e^{-} \to F e$ ; $E^{⊖} = - 0.036 V$

$F e^{2 +} + 2 e^{-} \to F e$ ; $E^{⊖} = - 0.440 V$

The $E^{⊖}$ of $F e^{3 +} + e^{-} \to F e^{2 +}$ is:

E_{F e^{2 +} / F e}^{\circ} = - 0.44 V and E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.77 V

E_{F e^{3 +} / F e}^{\circ}

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