If $E_{P}$ and $E_{k}$ represent potential energy and kinetic energy respectively, of an orbital electron, then according to Bohr's theory:

E_{k} = - E_{p} / 2

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E_{k} = - E_{p}

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E_{k} = - 2 E_{p}

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E_{k} = 2 E_{p}

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Solution

The correct option is D $E_{k} = - E_{p} / 2$
Potential energy of an orbital electron $E_{p} = - \frac{Z e^{2}}{r}$
Kinetic energy of an electron $E_{k} = \frac{Z e^{2}}{2 r}$ , where Z=atomic number
So, $E_{k} = - \frac{E_{p}}{2}$

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