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Transformers

If Ep and ...

Question

If $E_{p}$ and $E_{s}$ are the input and output voltages of a transformer, then:
(where $n_{p}$ is the number of turns in primary and $n_{s}$ is the number of turns in secondary)

\frac{E_{s}}{E_{p}} = \frac{n_{p}}{n_{s}}

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E_{s} E_{p} = n_{s} n_{p}

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E_{s} n_{p} = E_{p} n_{s}

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Solution

The correct option is C $E_{s} n_{p} = E_{p} n_{s}$
If Ep and Es are the input and output voltages of a transformer, then:
$\frac{E_{s}}{n_{s}} = \frac{E_{p}}{n_{p}}$

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\frac{E_{p}}{E_{s}} = \frac{n_{s}}{n_{p}}

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\frac{N_{S}}{N_{P}} = 4

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