MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Addition Theorem of Probability for 2 Events

If E represen...

Question

If E represents an event, P(E) + P(E’) = __

Open in App

Solution

P (E) + P(E’) = 1

P(sample space) = 1

S = E $\cup$ E’ where E and E’ are mutually exclusive events.

P(S) = P(E $\cup$ E’)= P(E) + P(E’) = 1

Suggest Corrections

thumbs-up

0

Similar questions

IF P (E) deonotes the probability of an event E then
(a) P(E) < 0 (b) P(E) > 1 (c) $0 \leq P (E) \leq 1$ (d) $- 1 \leq P (E) \leq 1$

Q. If P(E) denotes the probability of an event E then [CBSE 2013C]

(a) P(E) < 0
(b) P(E) > 1
(c) 0 ≤ P(E) ≤ 1
(d) −1 ≤ P(E) ≤ 1

Q. Fill in the blanks:
(i) Probability of a sure event = ..... .
(ii) Probability of an impossible event = ..... .
(iii) If E be an event, then P(E) + P(not E) = ..... .
(iv) If E is an event, then .......

\leq P (E) \leq

Q. If E & F are events with

P (E) \leq P (F)

P (E \cap F) > 0

P (E)

denotes the probability of an event

E

E

is called certain event if:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Addition rule

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Addition Theorem of Probability for 2 Events

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon