wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If ey+xy=e, the ordered pair (dydx,d2ydx2) at x=0 is equal to :

A
(1e,1e2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(1e,1e2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(1e,1e2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(1e,1e2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (1e,1e2)
Given equation, ey+xy=e,
As x=0y=1
ey dydx+xdydx+y=0 (1)
dydx=yey+x
At x=0, y=1dydx=1e
On differentiating (1) again, we have -
ey (dydx)2+ey d2ydx2+xd2ydx2+2dydx=0

At x=0, y=1
e(1e)2+ed2ydx22e=0

ed2ydx2=1e

d2ydx2=1e2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Higher Order Derivatives
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon