If E0 of MnO4(-1)/ Mn(+2) =1.51 V and E0 of MnO2/Mn(+2) =1.23 V,then standard electro de potential E0 of MnO4(-1 /MnO2 is

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\frac{M n O_{4}^{-}}{M n O_{2}}

E^{\circ} M n_{4}^{O -}, M n^{2 +} = 1.51 V E^{\circ} M n O_{2}^{-}, M n^{2 +} = 1.23 V

M n O_{4}^{-} | M n O_{2}

E_{M n O_{4}^{-} / M n^{2 +}}^{0} = 1.51 V E_{M n O_{2} / M n^{2 +}}^{0} = 1.23 V

M n O_{4}^{-} / M n O_{2}

M n O_{4}^{-} / M n^{2 +} = 1.51 V

M n O_{2} / M n^{2 +} = 1.23 V

25^{\circ} C

M n O_{2} \to M n^{3 +} E^{\circ} = 0.95 V

M n^{+ 3} \to M n^{2 +} E^{\circ} = 1.51 V

M n O_{2} \to M n^{2 +}

E^{0}

I . M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O E^{0} = 1.5 V

I I . S n^{2 +} \to S n^{4 +} + 2 e^{-} E^{0} = - 0.15 V

I I I . C r_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} \to 2 C r^{2 +} + 7 H_{2} O E^{0} = 1.33 V

I V . C e^{3 +} \to C e^{4 +} + e^{-} E^{0} = - 1.61 V

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