Question

If each art case comes with $15$ markers, $2$ eraser, $3$ sharpener, $9$ color pencils, and $5$ ruler, then how many total items will $101$ art cases contain?

• A. $2,255$
• B. $3,433$
• C. $2,050$

Answer 1

The correct option is B $3,433$

Number of markers in each art case $=15$
Number of markers in $101$ art case $=15\times 101$

$15\times 101$ can be evaluated using method:

$15\times 101=(10+5)\times 101$

Distributive Property: The product of a number with a sum, is equal to the sum of the products.

$15\times 101=10\times 101+5\times 101$
$15\times 101=1,010+505$
$15\times 101=1,515$

Number of markers in $101$ art cases $=1,515$

Number of markers in $101$ art cases $=1,515$

Number of erasers $=101\times 2=202$

Number of sharpeners $=101\times 3=303$

Number of color pencils $=101\times 9=909$

Number of rulers $=101\times 5=505$

Total number of items in $101$ art cases $=1,515+202+302+909+505=3433$