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Question
If each of the odd digits in the number 5 4 6 3 8 is decreased by 1, and each of the even digits is increased by 1, then which of the following will be the sum of the digits of the new numbers?
If each of the odd digits in the number 5 4 6 3 8 is decreased by 1, and each of the even digits is increased by 1, then which of the following will be the sum of the digits of the new numbers?
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Solution
The correct option is E None of these
The new number formed is 4 5 7 2 9.
∴ Required sum of the digits = 4+5+7+2+9 = 27
Alternative method: sum of the digits of the given number 54638 is 26. There are two odd numbers and three even numbers. Since an odd number is decreased by 1 and even number is increased by 1 so the net increase in the sum of the digits is 3 - 2 i.e. 1
Hence the new sum is 26 + 1 i.e. 27.
The new number formed is 4 5 7 2 9.
∴ Required sum of the digits = 4+5+7+2+9 = 27
Alternative method: sum of the digits of the given number 54638 is 26. There are two odd numbers and three even numbers. Since an odd number is decreased by 1 and even number is increased by 1 so the net increase in the sum of the digits is 3 - 2 i.e. 1
Hence the new sum is 26 + 1 i.e. 27.
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