If each of the points (x1,4),(−2,y1) lies on the line joining the points (2,−1) and (5,−3), then find x1+y1
A
−136
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B
32
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C
−336
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D
−236
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Solution
The correct option is D−236 First we need to find the equation of the line joining the points (2,−1) and (5,−3)
Using two point form : y+1=−1+32−5(x−2) y+1=2−3(x−2)
-3(y+1)=2(x−2) ⇒2x+3y−1=0
Since (x1,4) and (−2,y1) lie on the line 2x+3y−1=0, therefore 2x1+12−1=0⇒x1=−112
and −4+3y1−1=0⇒y1=53
Thus, (x1+y1) = 53 +(−112) ⇒10−336 ⇒−236