Question

If each resistance in the figure is of $9\Omega$ then reading of ammeter is

• A. 5 A
• B. 8 A
• C. 2 A
• D. 9 A

Answer 1

The correct option is A 5 A

Main current through the battery $i=\frac{9}{1}=9A$. Current through each resistance will be 1A and only 5 resistances on the right side of ammeter contributes for passing current through the ammeter. So reading of ammeter will be 5A.