If each term of an infinite G.P. is twice the sum of the terms following it, then the common ratio of G.P. is
A
12
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B
13
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C
14
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D
15
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Solution
The correct option is B13 Let a be the first term and r the common ratio of the G.P.
Then, an=2[an+1+an+2+an+3+⋯], for all n∈N [Given] ⇒arn−1=2[arn+arn+1+⋯] ⇒arn−1=2arn1−r ⇒1=2r1−r ⇒r=13