Given, if either a → =0 or b → =0 then a → ⋅ b → =0.
Assume, a → =( i ^ + j ^ + k ^ ) and b → =( i ^ −2 j ^ + k ^ ).
Dot product of vectors is,
a → ⋅ b → =( i ^ + j ^ + k ^ )⋅( i ^ −2 j ^ + k ^ ) =1⋅1+1⋅( −2 )+1⋅1 =0
Here, a → ⋅ b → =0. But, a → ≠0 and b → ≠0.
Thus, the converse of the statement need not be true.
If either a = 0 or b = 0, then a.b = 0. But the converse need not to be true. Justify your answer with an example.