If electric potential in a region is given by V -400- r- where r is the distance of point from origin then- E in this regionA- is along tangentB- is along radially inward directionC- is along radially outward directionD- is zero

The correct option is C is along radially outward direction nbsp;As V = 400/r, then the equipotential surfaces must be spherical. We know that, E= dV/dr. A ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Electric Potential at a Point in Space Due to a Point Charge Q

If electric p...

Question

If electric potential in a region is given by $V = \frac{400}{r}$ , where $r$ is the distance of point from origin then, $\to E$ in this region

is along tangent

No worries! We‘ve got your back. Try BYJU‘S free classes today!

is along radially inward direction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

is along radially outward direction

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

is zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C is along radially outward direction
As $V = \frac{400}{r},$ then the equipotential surfaces must be spherical.

We know that, $\to E = - \frac{d V}{d r}$ .
As $V$ is decreasing in radially outward direction, so $\to E$ must be in radially outward direction.

Suggest Corrections

Similar questions

Q. The electric field in a region is radially outward and at a point is given by

E = 250 r

V/m (where

r

is the distance of the point from origin). Calculate the charge contained in a sphere of radius

20

cm centred at the origin

Q. The electric field in a region is radially outward and is given by

E = 250 r V/m

at a point (where

r

is the distance of the point from the origin). Calculate the charge contained in a sphere of radius

20 cm

centred at the origin.

Q. If the electric potential along a line due to a charge is given by

V (r) = \frac{25}{r} + 3

, where r is the distance from the charge, what is the electric field at a point r = 5 along this line?

Q. If electric field in a region is radially outward with magnitude

E = A r

, the charge contained in a sphere of radius

r

centred at the origin is :

Q. A particle is projected along a horizontal field whose coefficient of friction varies as

μ

A / r^{2}

, where r is the distance from the origin in metres and A is a positive constant. The initial distance of the particle is 1 m from the origin and its velocity is radially outwards. The minimum initial velocity at this point so the particle never stops is

Join BYJU'S Learning Program

If electric potential in a region is given by V=400r, where r is the distance of point from origin then, →E in this region

The correct option is C is along radially outward direction As V=400r, then the equipotential surfaces must be spherical. We know that, →E=−dVdr. As V is decreasing in radially outward direction, so →E must be in radially outward direction.

If electric potential in a region is given by $V = \frac{400}{r}$ , where $r$ is the distance of point from origin then, $\to E$ in this region

The correct option is C is along radially outward direction
As $V = \frac{400}{r},$ then the equipotential surfaces must be spherical.

We know that, $\to E = - \frac{d V}{d r}$ .
As $V$ is decreasing in radially outward direction, so $\to E$ must be in radially outward direction.