If elements with principal quantum number n> 4 were not allowed in nature, the number of possible elements would be

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Solution

The correct option is D 60
Maximum value of n = 4
So possible (maximum) no. of elements
$N = 2 \times 1^{2} + 2 \times 2^{2} + 2 \times 3^{2} + 2 \times 4^{2} = 2 + 8 + 18 + 32 = 60$

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If elements with principal quantum number n>4 were not allowed in nature, the number of possible elements would be

^{'} n^{'}

n > 4

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