If elements with principal quantum number $n > 4$ were not allowed in nature, the number of possible elements would have been

32

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60

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18

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4

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Solution

The correct option is B $60$
The no. of electrons in $n^{t h}$ shell is $2 n^{2}$ .
$\sum_{1}^{4} 2 n^{2} = 60$

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If elements with principal quantum number $n > 4$ were not allowed in nature, the number of possible elements would have been :

^{'} n^{'}

n > 4

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