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Question

If 2+m2=1 then the maximum value of +m is

A
1
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B
2
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C
12
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D
2
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Solution

The correct option is C 2
l2+m2=1m21l2m=1l2
Let
y=l+m=l+1l2dydl=1+121l2×2ldydl=012l21l2=01=l1l21l2=l2x2=1l=12
maximum value of l+m=l+1l2=12+11(2)2=12+12=22=2

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