If enthalpy of an overall reaction X $\to$ Y along one route is $△$ _rH and $△_{r} H_{1}$ , $△_{r} H_{2}$ , $△_{r} H_{3} . . . . .$ representing enthalpies of reactions leading to same product Y then, $△_{r} H$ is :

△_{r} H = △_{r} H_{1} + △_{r} H_{2} + △_{r} H_{3} . . . . .

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△_{r} H = △_{r} H_{1} X △_{r} H_{2} X △_{r} H_{3} . . . . .

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△_{r} H = △_{r} H_{1} + △_{r} H_{2} - △_{r} H_{3} . . . . .

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△_{r} H = \frac{△_{r} H_{1} X △_{r} H_{2} X △_{r} H_{3}}{2} . . . . . . .

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Solution

The correct option is A $△_{r} H = △_{r} H_{1} + △_{r} H_{2} + △_{r} H_{3} . . . . .$
According to Hess's law,
$Δ_{r} H = Δ_{r} H_{1} + Δ_{r} H_{2} + Δ_{r} H_{3}$ .......
Where $H_{1}$ , $H_{2}$ , $H_{3}$ , etc. are enthalpies of various steps

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