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Question

If enthalpy of formation of CH3−CH3(g),CH3−CH2−CH3(g)andCH3−CH2−CH2−CH3(g) are 20 kcal /mole,25 kcal /mol and 30 kcal/mol respectively, then enthalpy of formation of CH3−CH2−CH2−CH2−CH2−CH3 (g) is:

A
50 kcal/mol
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B
40 kcal/mol
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C
45 kcal/mol
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D
35 kcal/mol
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E
55 kcal/mol
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Solution

The correct option is B 40 kcal/mol
If enthalpy of formation of CH3CH3 (g),
The enthalpy of formation per CH2 group
=5kcal/mol.
Hence enthalpy of formation of C6H14
=305×2
=40kcal/mol.

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