If equal concentrations of products and reactants are mixed, then which of the following reactions will proceed to the right and which will proceed to the left?
(A) $H_{2} S O_{4} (a q) + N H_{3} (a q) ⇌ {N H}_{4}^{+} (a q) + {H S O}_{4}^{-} (a q)$
(B) ${H C O}_{3}^{-} (a q) + {S O}_{4}^{2 -} (a q) ⇌ {H S O}_{4}^{-} (a q) + C O_{3}^{2 -} (a q)$ .

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Solution

If equal concentrations of products and reactants are mixed then both of the reactions will attain its chemical equilibrium. It will proceed in both directions. Ciz. forward & backward at the same rate. This observation can be easily concluded as a result of Le Chaterlier's principle.

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