If equal volume of ${B a C l}_{2}$ and $N a F$ solutions are mixed , which of these combination will give a precipitate?
$K_{s p}$ of ${B a F}_{2} = {1.7 \times 10}^{- 7} .$

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Solution

If equal of $B a C I 2 (a q)$ and $N a F (a q)$ solution are mixed together, which will NOT give a precipitate $(K s p o f B a F 2 = 1.7 \times 10 - 7) ?$
this is correct question

a. all will produce a precipitate
b. $0.0040 M B a C l 2$ and $0.020 M N a F$
c. $0.010 M B a C l 2$ and $0.0020 M N a f$
d. $0.020 M = B a C l 2$ and $0.0020 M N a F$
e. $0.0150 M B a C l 2$ and $0.010 M N a F$

Only tune mixture will precipitate which have greater ionic product then $K s p$ value
$K s p (B a F_{2}) = [B a + 2] [F^{-}]^{2}$

(b) ionic produced $= 0.0040 \times (0.02)^{2} = 1 \times 10^{- 7}$
it will give precipitate

(c) ionic product $= 0.010 \times (0.015)^{2} = 22.5 \times 10^{- 7}$
it will also give precipitate

(d) ionic product $= 0.02 \times (0.002)^{2} = 0.8 \times 10^{- 7}$
it will not give precipitate

(e) ionic product $= 0.016 \times (0.010)^{2}$
$= 15 \times 10^{- 7}$
it will also give precipitate
only option $c$ will not give precipitate

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