If equal volumes of $0.1 M K M n O_{4}$ and $0.1 M K_{2} C r_{2} O_{7}$ solutions are allowed to oxidise $F e^{2 +} t o F e^{3 +}$ in acidic medium, then $F e^{2 +}$ oxidised will be :

more by

K M n O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

more by

K_{2} C r O_{7}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

equal in both cases

No worries! We‘ve got your back. Try BYJU‘S free classes today!

can't be determined

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A more by $K_{2} C r O_{7}$
$C r$ changes from +6 to +3 oxidation state on reduction. But there are two $C r$ atoms per molecule, net change is $2 \times 3 = 6$ .

$M n$ changes from +7 to +2 on reduction. So, change is $5$ .

Hence, for equal molar and volume solutions of $K_{2} C r O_{7}$ and $K M n O_{4}$ , more oxidation occurs from $K_{2} C r O_{7}$ .

Suggest Corrections

Similar questions

If equal volumes of 0.1 M $K M n O_{4}$ and $0.1 M K_{2} C r_{2} O_{7}$ solutions are allowed to oxidise $F e^{2 +}$ to $F e^{3 +}$ in acidic medium, then $F e^{2 +}$ oxidized will be:

Q. If equal volumes of

1 M

K M n O_{4}

and

1 M

K_{2} C r_{2} O_{7}

solutions are used to oxidise

F e^{2 +}

in acidic medium, then

F e^{2 +}

will be oxidised

Q. If equal volumes of 0.1

M K M n O_{4}

and 0.1

M K_{2} C r_{2} O_{7}

solutions are allowed to oxidise

F e^{2 +}

F e^{3 +}

in acidic medium, then

F e^{2 +}

oxidised will be:

Q. Equal volumes of 1 M each of

K M n O_{4}

and

K_{2} C r_{2} O_{7}

are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be:

Q. Ratio of moles of Fe(||) oxidised by equal volumes of equimolar KMnO₄ and K₂Cr₂O₇ solutions in acidic medium will be:

Join BYJU'S Learning Program

If equal volumes of 0.1MKMnO4 and 0.1MK2Cr2O7 solutions are allowed to oxidise Fe2+toFe3+ in acidic medium, then Fe2+ oxidised will be :

If equal volumes of $0.1 M K M n O_{4}$ and $0.1 M K_{2} C r_{2} O_{7}$ solutions are allowed to oxidise $F e^{2 +} t o F e^{3 +}$ in acidic medium, then $F e^{2 +}$ oxidised will be :