If equal volumes of $11$ M $K M n O_{4}$ and $1$ M $K_{2} C r_{2} O_{7}$ solutions are allowed to oxidise $F e (I I)$ to $F e (I I I)$ , then $F e (I I)$ oxidised will be:

more by

K M n O_{4}

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more by

K_{2} C r_{2} O_{7}

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equal in both cases

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data is incomplete

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Solution

The correct option is B more by $K_{2} C r_{2} O_{7}$
${M n O_{4}}^{-} + 5 F e^{2 +} \to 5 F e^{3 +} + {M n O_{4}}^{-}$
${C r_{2} O_{7}}^{-} + 6 F e^{2 +} \to 6 F e^{3 +} + 2 C r^{3 +}$
From balance equations, it can be seen that ${C r_{2} O_{7}}^{-}$ oxidizes more $F e^{2 +}$ .

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Similar questions

Equal volumes of 1 M each of $K M n O_{4}$ and $K_{2} C r_{2} O_{7}$ are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be :

Q. Equal volumes of 1 M each of

K M n O_{4}

and

K_{2} C r_{2} O_{7}

are used to oxidise Fe(II) solution in acidic medium. The amount of Fe oxidized will be:

Q. If equal volumes of

1 M

K M n O_{4}

and

1 M

K_{2} C r_{2} O_{7}

solutions are used to oxidise

F e^{2 +}

in acidic medium, then

F e^{2 +}

will be oxidised

Q. Ratio of moles of Fe(||) oxidised by equal volumes of equimolar KMnO₄ and K₂Cr₂O₇ solutions in acidic medium will be:

Ratio of moles of Fe(II) oxidized by equal volumes of equimolar $K M n O_{4}$ and $K_{2} C r_{2} O_{7}$ solutions in acidic medium. $K_{P}$ will be

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If equal volumes of 11 M KMnO4 and 1 M K2Cr2O7 solutions are allowed to oxidise Fe(II) to Fe(III), then Fe(II) oxidised will be:

The correct option is B more by K2Cr2O7MnO4−+5Fe2+→5Fe3++MnO4−Cr2O7−+6Fe2+→6Fe3++2Cr3+From balance equations, it can be seen that Cr2O7− oxidizes more Fe2+.

If equal volumes of $11$ M $K M n O_{4}$ and $1$ M $K_{2} C r_{2} O_{7}$ solutions are allowed to oxidise $F e (I I)$ to $F e (I I I)$ , then $F e (I I)$ oxidised will be:

The correct option is B more by $K_{2} C r_{2} O_{7}$
${M n O_{4}}^{-} + 5 F e^{2 +} \to 5 F e^{3 +} + {M n O_{4}}^{-}$
${C r_{2} O_{7}}^{-} + 6 F e^{2 +} \to 6 F e^{3 +} + 2 C r^{3 +}$
From balance equations, it can be seen that ${C r_{2} O_{7}}^{-}$ oxidizes more $F e^{2 +}$ .